The upper half of an inclined plane of inclination theta is perfectly

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For first half acceleration = g sin theta Therefore, velocity after travelling ball distance v^(2) = 2(g sin theta)l For second half, acceleration = g(sin theta - mu(k) cos theta) so 0^(2) = v^(2) = 2g (sin phi - mu(k) cos phi)l Solving (i) and (ii) we get mu(k) = 2 tan theta

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The upper half of an inclined plane of inclination andtheta; is perfectly smooth while lower half is rough. A blockstarting from rest at the top of the plane will again come to

The upper half of an inclined plane of inclination is perfectly smooth while the lower half rough. A block starting from rest the of the plane will again come to rest the

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Solved] The upper half of an inclined plane of inclination &the

Solved] the upper half of an inclined plane with inclination (theta) is perfectly smooth while the lower

CU 10. W TOUN (B) 500N (l) 349 N The upper half of an inclined plane of inclination is perfectly smooth while the lower half is rough. A body starting from the

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The upper half of an inclined plane of inclination θ is perfectly smooth while the lower half rough. A block starting from rest at the top of the plane will again come

10. The upper half of an inclined plane of inclination o is perfectly smooth while lower half is rough. A block starting from rest the of the plane will again come to