∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in

∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in Figure). The height AD from A to BC, is 6 cm. Find the area of ∆ ABC. What will be the height from C to AB i.e., CE?

ABC is an isosceles triangle with ab is equal to AC is equal to

∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in

∆ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (Fig 9.17

8. frac{1}{D} frac{13 mathrm{cm}}{mathrm{D} 13 mathrm{cm}} mathrm

Triangle ABC is isosceles with AB = AC = 7.5cm and BC=9cm. The

Class 7 - Exercise 11.2 - Q 8 Triangle is isosceles with AB = AC

DeltaABC is isosceles with AB=AC=7.5cm and BC=9cm. The height AD

Let a triangle ABC AB=14, BC=13, AC=15 cm. If AD and BE are angle

how to solve this isosceles triangle when AB=AC =17.5cm and BC